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x^2+90x-5100=0
a = 1; b = 90; c = -5100;
Δ = b2-4ac
Δ = 902-4·1·(-5100)
Δ = 28500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28500}=\sqrt{100*285}=\sqrt{100}*\sqrt{285}=10\sqrt{285}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-10\sqrt{285}}{2*1}=\frac{-90-10\sqrt{285}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+10\sqrt{285}}{2*1}=\frac{-90+10\sqrt{285}}{2} $
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